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x-3(x-1)^2=4-5(x-1)
We move all terms to the left:
x-3(x-1)^2-(4-5(x-1))=0
We calculate terms in parentheses: -(4-5(x-1)), so:We get rid of parentheses
4-5(x-1)
determiningTheFunctionDomain -5(x-1)+4
We multiply parentheses
-5x+5+4
We add all the numbers together, and all the variables
-5x+9
Back to the equation:
-(-5x+9)
x-3(x-1)^2+5x-9=0
We add all the numbers together, and all the variables
6x-3(x-1)^2-9=0
We move all terms containing x to the left, all other terms to the right
6x-3(x-1)^2=9
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